The any Type
A free lesson from Swipe Coding · TypeScript, level 2 · updated October 2026
By the Swipe team, founded by Colin · how we make lessons
Every TypeScript value has a type, but sometimes you need a variable that can hold literally anything and have TypeScript stay completely out of the way. That's what the any type is for — it's an escape hatch that opts a value out of type checking entirely.
let value: any = 4; value = "hello"; // fine, no error value = true; // fine, no error value = [1, 2, 3]; // fine, no error
The real danger of any isn't just that it accepts anything — it's that TypeScript stops checking what you do with it, too. Calling a method that doesn't exist, accessing a property that was never there, passing it somewhere it doesn't belong — all of that compiles without a single warning.
let data: any = { name: "Ada" };
data.nonExistentMethod(); // compiles fine...
// ...then crashes at runtime:
// TypeError: data.nonExistentMethod is not a functionReaching for any every time a type is inconvenient to write defeats the entire purpose of using TypeScript — you get the extra syntax and the build step, but lose the safety net that's supposed to come with them. any has legitimate uses (gradually migrating old JavaScript, for example), but it should be the exception, not the default.
// Overusing any — silently unsafe:
function total(items: any): number {
return items.reduce((sum: any, i: any) => sum + i.price, 0);
}
// Prefer a real type instead:
function totalSafe(items: { price: number }[]): number {
return items.reduce((sum, i) => sum + i.price, 0);
}A variable typed as ____ can be reassigned to any type with no compiler error.
Why is overusing any considered risky in a TypeScript codebase?
Calling a nonexistent method on a value typed any produces a compile-time error.
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